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Solution
1. Figure (a)
- The graph in Figure (a) includes the subgraph C5C5 (observe the outer 5 vertices).
- If the graph is 2-colorable, it must have an even number of vertices. However, C5C5 has an odd number of vertices (5).
- Thus, χ(C5)≥3χ(C5)≥3.
- Below is Figure (a):

- I marked the graph with 3 proper colors (1, 2, 3). It is 3-colorable.
- Therefore, χ(graph (a))=3χ(graph (a))=3.
2. Figure (b)
- The graph in Figure (b) also contains C5C5. I highlighted it with a yellow line.
- For the same reason as mentioned above, the chromatic number of this graph is at least 3.
- Below is Figure (b):

- I marked the graph with 3 proper colors (1, 2, 3). It is 3-colorable.
- Therefore, χ(graph (b))=3χ(graph (b))=3.
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