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Graph Theory

Let F be a maximal forest of G. Show that: e(F)=n(G)c(G), where e, n, and c are the number of edges, vertices, and compo-nents, respectively.

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문제출처

광주과학기술원 GIST 최정옥 교수님의 “그래프 이론” 수업, 2024년 가을학기 중 Homework 5

Solution

1. G has c(G) components. Each component H of G is connected and contains a spanning tree FH, as shown in part (a).

2. A spanning tree with k vertices has exactly k1 edges, since a tree with k vertices has k1 edges by definition.

3. Therefore, for each component H, if H has n(H) vertices, the spanning tree FH has n(H)1 edges.

4. Now, summing over all components of G, the total number of edges in the forest F is the sum of (n(H)1) over all components H:
e(F)=H(n(H)1).

5. Since the sum of the number of vertices in all components is the total number of vertices n(G), and there are c(G) components, this simplifies to:
e(F)=n(G)c(G).

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